Validate the user’s input with while, break, and continue

See break and continue. We saw the try and except here.

validate.py

Please type an integer in the range 1 to 10 inclusive: hello
Sorry, hello is not an integer.
Please type an integer in the range 1 to 10 inclusive: 5.6
Sorry, 5.6 is not an integer.
Please type an integer in the range 1 to 10 inclusive: 11
Sorry, 11 is not in the range 1 to 10 inclusive.
Please type an integer in the range 1 to 10 inclusive: 0
Sorry, 0 is not in the range 1 to 10 inclusive.
Please type an integer in the range 1 to 10 inclusive: 7
Thank you.  7 is acceptable.

Things to try

1. Unlike most languages, Python lets you abbreviate

       if 1 <= i and i <= 10:
   

   to

       if 1 <= i <= 10:
   

   See Chained.


2. Make a user-defined function.

   """
   validate.py
   
   Keep prompting the user until he or she inputs an integer in the range 1 to 10
   inclusive.
   """
   
   import sys
   
   def getInt(prompt):
       """
       Let the user input one integer.
       """
       assert isinstance(prompt, str)
   
       while True:
           try:
               s = input(prompt + " ")
           except EOFError:
               sys.exit(1)
   
           try:
               i = int(s)
           except ValueError:
               print(f"Sorry, {s} is not an integer.  Try again.")
               continue    #Go back up to the word while
   
           return i
   
   
   while True:
       i = getInt("Please type an integer in the range 1 to 10 inclusive:")
   
       if 1 <= i and i <= 10:
           break
   
       print(f"Sorry, {i} is not in the range 1 to 10 inclusive.  Try again.")
   
   print(f"Thank you.  {i} is acceptable.")
   sys.exit(0)
   



3. Give the user only three chances to type in a valid number. If he or she hasn’t done it by then, exit the script with exit status 1.