Hexadecimal (base 16) notation for memory addresses

A binary digit or bit is a 0 or a 1. Thus a bit has one of two possible values.
A series of 8 bits is called a byte. For example, 01010101.
A series of 4 bits is called a nibble. For example, 0101.

A computer’s memory is a series of containers called cells. Each cell holds one byte.

Each cell has an identifying number, called its memory address.
On our machine storm.cis.fordham.edu, a memory address is conventionally written in hexadecimal notation.
That’s why the number 9 in the following diagram is followed by A and B instead of by 10 and 11.

On our machine, a C++ value of data type int occupies 32 bits of memory, so we use four consecutive cells to hold it.
For example, the memory in the diagram uses cells number 4 through 7 inclusive to hold the 32-bit int value 2025.

	int i {2025};

Let’s see how to write a number in binary (base 2) and hexadecimal (base 16).

The digits of a number (2025) written in decimal (base 10)

Each place has 10 times the value of the previous one.
Depending on the number, we might need to write ten decial digits: 0, 1, 2, 3, 4, 5, 6, 7, 8, 9.

1000’s
place
100’s
place
10’s
place
1’s
place
2 0 2 5




2 × 1000 = 2000
0 ×  100 =    0
2 ×   10 =   20
5 ×    1 =    5
           2025

The digits of the same number (2025), written in binary (base 2)

Each place has 2 times the value of the previous one.
The only binary digits we will ever need to write are 0 and 1.

1024’s
place
512’s
place
256’s
place
128’s
place
64’s
place
32’s
place
16’s
place
8’s
place
4’s
place
2’s
place
1’s
place
1 1 1 1 1 1 0 1 0 0 1




1 × 1024 = 1024
1 ×  512 =  512
1 ×  256 =  256
1 ×  128 =  128
1 ×   64 =   64
1 ×   32 =   32
0 ×   16 =    0
1 ×    8 =    8
0 ×    4 =    0
0 ×    2 =    0
1 ×    1 =    1
           2025

Our number 2025 consists of a series of 11 bits when written in binary.
We will usually consider bits in groups of 4 or 8 at a time, so let’s expand our 11-bit number to 16 bits by adding 5 leading 0’s.
Now our number 2025 consists of 2 complete bytes, because 2 = 16/8.

32768’s
place
16384’s
place
8192’s
place
4096’s
place
2048’s
place
1024’s
place
512’s
place
256’s
place
128’s
place
64’s
place
32’s
place
16’s
place
8’s
place
4’s
place
2’s
place
1’s
place
0 0 0 0 0 1 1 1 1 1 1 0 1 0 0 1




0 × 32768 =    0
0 × 16384 =    0
0 ×  8192 =    0
0 ×  4096 =    0
0 ×  2048 =    0
1 ×  1024 = 1024
1 ×   512 =  512
1 ×   256 =  256
1 ×   128 =  128
1 ×    64 =   64
1 ×    32 =   32
0 ×    16 =    0
1 ×     8 =    8
0 ×     4 =    0
0 ×     2 =    0
1 ×     1 =    1
            2025

Abbreviate the 16 bits with 4 hex digits.

As we just saw, writing the value of a number in binary usually takes many bits. That’s why they invented hexadecimal digits. Each hexadecimal digit (hex digit) stands for a series of 4 binary digits (bits). In other words, each hex digit stands for 1 nibble.

Here are the 16 nibbles that the 16 hex digits stand for.

hex digit nibble
(4 bits)
0 0000
1 0001
2 0010
3 0011
4 0100
5 0101
6 0110
7 0111
8 1000
9 1001
A 1010
B 1011
C 1100
D 1101
E 1110
F 1111

We can now write out 16-bit number (2025 = 0000011111101001) with only 4 hex digits (07E9):

  32768’s
place
16384’s
place
8192’s
place
4096’s
place
2048’s
place
1024’s
place
512’s
place
256’s
place
128’s
place
64’s
place
32’s
place
16’s
place
8’s
place
4’s
place
2’s
place
1’s
place
binary 0 0 0 0 0 1 1 1 1 1 1 0 1 0 0 1
hex 0 7 E 9




Conversion programs

Type control-d into the first two programs to signal that you’re done typing.

  1. dectohex.C: convert base 10 to base 16.
  2. hextodec.C: convert base 16 to base 10.
  3. table.C: decimal (base 10) and hexadecimal (base 16), side by side.